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填空(x﹣y)(x2+xy+y2)= ;(x﹣y)(x3+x2y+xy2+y3)= 根据以上等式进行猜想,当n是偶数时,可得:(x﹣y)(xn+xn﹣1y+yn﹣2y2+…+x2yn﹣2+xyn﹣1+yn)= .
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