如图,将△ABC绕着点C顺时针旋转50°后得到△A′B′C′.若∠A=40°.∠B′=110°,则∠BCA′的度数是 ( )
A.30° | B.40° | C.80° | D.110° |
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如图,将△ABC绕着点C顺时针旋转50°后得到△A′B′C′.若∠A=40°.∠B′=110°,则∠BCA′的度数是 ( )
A.30° | B.40° | C.80° | D.110° |
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