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先化简,再求值: 1 - y - x x + 2 y ÷ x 2 - y 2 x 2 + 4 xy + 4 y 2 ;其中 x = cos 30 ° × 12 , y = ( π - 3 ) 0 - ( 1 3 ) - 1 .
先化简,再求值: m − 3 m − 2 ÷ ( m + 2 − 5 m − 2 ) ,其中 m = ( 1 3 ) − 1 + ( 2 − π ) 0 + 8 − | − 7 | .
计算: | - 3 | + 8 - 2 .
(1)计算: 4 × ( - 3 ) + | - 8 | - 9 + ( 7 ) 0 .
(2)化简: ( a - 5 ) 2 + 1 2 a ( 2 a + 8 ) .
计算: | - 2 | + ( 1 3 ) 0 - 9 + 2 sin 30 ° .
(1)计算: ( - 1 ) 2 - ( π - 2021 ) 0 + | - 1 2 | ;
(2)如图,在 ΔABC 中, ∠ A = 40 ° , ∠ ABC = 80 ° , BE 平分 ∠ ABC 交 AC 于点 E , ED ⊥ AB 于点 D ,求证: AD = BD .
(1)计算: ( 2020 ) 0 - 4 + | - 3 | ;
(2)化简: ( a + 2 ) ( a - 2 ) - a ( a + 1 ) .
(1)计算: ( π - 3 ) 0 - 12 + 4 sin 60 ° - ( 1 2 ) - 1 ;
(2)化简: ( 2 a - 1 + 1 ) ÷ a 2 + a a 2 - 2 a + 1 .
计算: 9 - 1 = .
(1)计算 ( - 1 2 ) - 1 - 3 tan 60 ° + - 3 + ( 2 cos 60 ° - 2020 ) 0 ;
(2)解不等式组: 3 - x 2 ≤ 1 3 x + 2 ≥ 4 .
计算: | 3 | - ( π - 1 ) 0 = .
(1)计算: 4 sin 60 ° - 12 + ( 2 - 3 ) 0 .
(2)解不等式: 5 x + 3 ⩾ 2 ( x + 3 ) .
(1)计算: ( 1 2 ) - 2 + ( 3 . 14 - π ) 0 + | 3 - 12 | - 4 sin 60 ° .
(2)先化简,再求值: ( 1 x - 1 - x + 1 ) ÷ x - 2 x 2 - 1 ,其中 x = 2 - 1 .
计算: - 8 3 + 16 = .
计算:
(1) | - 8 | × 2 - 1 - 16 + ( - 1 ) 2020 ;
(2) ( a + 2 ) ( a - 2 ) - a ( a + 1 ) .
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