0.3mol的气态高能燃料乙硼烷B2H6在O2中燃烧，生成固态B2O3和液态H2O，放出649.5kJ的热量。又知H2O(l) ＝ H2O(g) △H="+44kJ" /mol
下列热化学方程式中，正确的是　                                       (     )

A．B2H6(g)＋3O2(g)==B2O3(s)＋3H2O(l)△H ="+2165kJ" /mol

B．B2H6(g)＋3O2(g)==B2O3(s)＋3H2O(g)△H ="-2033kJ" /mol

C．B2H6＋3O2 ==B2O3＋3H2O△H ="-2165kJ" /mol

D．B2H6(g)＋O2(g)==B2O3(s)＋H2O(g)△H ="-2165kJ" /mol