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计算:
(1) ( 2 2 ) 2 - | - 4 | + 3 - 1 × 6 + 2 0 .
(2) x - 2 x - 1 · x 2 - 1 x 2 - 4 x + 4 - 1 x - 2 .
(1)计算: ( - 2 ) 3 + ( 1 3 ) - 2 - 8 · sin 45 °
(2)分解因式: ( y + 2 x ) 2 - ( x + 2 y ) 2 .
(1)计算: ( - 3 ) 2 - ( 1 5 ) - 1 - 8 × 2 + ( - 2 ) 0
(2)先化简,再求值: 2 x 2 - 2 x x 2 - 1 - x x + 1 ,其中 x = - 2 .
计算: | 3 - 1 | - 2 × 6 + 1 2 - 3 - 8 2 3
计算: 18 + ( 2 - 1 ) 2 - 9 1 2 + ( 1 2 ) - 1 .
计算: | 3 - 1 | - 4 1 2 - 12 + ( 1 3 ) - 2 .
计算: - 2 × - 27 3 + | 1 - 3 | - ( 1 2 ) - 2
计算: - 2 × ( 3 ) 2 + | 5 - 3 | - ( - 65 ) 0 .
计算: ( - 3 ) × ( - 6 ) + | 2 - 1 | + ( 5 - 2 π ) 0
计算:.
计算: ( - 2 ) × 6 + | 3 - 2 | - ( 1 2 ) - 1 .
计算: 18 - ( π - 5 ) 0 + | 2 2 - 3 | .
计算: 12 - | 1 - 3 | + ( 7 + π ) 0 .
计算: ( - 3 ) 2 + | 2 - 5 | - 20 .
(1)计算:;
(2)如图,四边形中,,,对角线,相交于点,且.求证:四边形是矩形.
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