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计算 ( a - 1 + 1 a + 1 ) ÷ a 2 + 2 a a + 1 .
计算:
(1);
(2).
化简: ( a 2 a - 1 - a - 1 ) ÷ 2 a a 2 - 1 .
化简:.
(1)化简:;
(2)解不等式组,并写出它的正整数解.
计算:.
(1)计算:
(2)化简:
化简 ( a - b 2 a ) ÷ a - b a 的结果是 ( )
a - b
a + b
1 a - b
1 a + b
(1)计算:;
(2)计算:.
(1) ( x + y ) 2 - y ( 2 x + y )
(2) ( a + 9 - 4 a a - 2 ) ÷ a 2 - 9 a - 2
(1) ( x + 2 y ) 2 - ( x + y ) ( x - y ) ;
(2) ( a - 1 - 4 a - 1 a + 1 ) ÷ a 2 - 8 a + 16 a + 1
(1) a ( a + 2 b ) - ( a + b ) ( a - b )
(2) ( x + 2 x - 3 + x + 2 ) ÷ x 2 - 4 x + 4 x - 3
(1) ( x + y ) 2 - x ( 2 y - x ) ;
(2) ( a + 2 - 3 a - 4 a - 2 ) ÷ a 2 - 6 a + 9 a - 2 .
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