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先化简,再求值: 1−a2+4ab+4b2a2−ab÷a+2ba−b,其中 a、 b满足 (a−√2)2+√b+1=0.
(1)计算: |√3−1|+(−1)2017+4sin60°+√4.
(2)先化简再求值: (1x−y−1x+y)÷2yx−y,其中 x、 y满足 |x−1|+(y+2)2=0.
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