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已知函数f0(x)=sinxx(x>0),设fn(x)为fn-1(x)的导数,n∈N*
(1)求2f1(π2)+π2f2(π2)的值; (2)证明:对任意n∈N*,等式nfn-1(π4)+π4fn(π4)=22.
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