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先化简,再求值: 1 - y - x x + 2 y ÷ x 2 - y 2 x 2 + 4 xy + 4 y 2 ;其中 x = cos 30 ° × 12 , y = ( π - 3 ) 0 - ( 1 3 ) - 1 .
计算: - 8 3 + | 3 - 1 | - 2 sin 60 ° + ( 1 4 ) 0 .
计算: ( - 1 2 ) - 1 - | - 2 | + 4 sin 60 ° - 12 + ( π - 3 ) 0 .
计算: ( 1 2 ) - 1 - | - 2 | + 2020 0 .
计算求解:
(1)计算 ( 1 3 ) − 1 − ( 80 − 20 ) ÷ 5 + 3 tan 30 ° ;
(2)解方程组 1 . 5 ( 20 x + 10 y ) = 15000 1 . 2 ( 110 x + 120 y ) = 97200 .
(1)计算:;
(2)先化简,再求值:,其中从,2,3中取一个你认为合适的数代入求值.
计算: ( 2 - 2 ) 0 + ( - 1 2 ) - 2 + 2 sin 45 ° - 8 .
(1)计算;
(2)先化简,再求值:,其中.
计算: | - 3 | + 8 - 2 .
(1)计算: 4 × ( - 3 ) + | - 8 | - 9 + ( 7 ) 0 .
(2)化简: ( a - 5 ) 2 + 1 2 a ( 2 a + 8 ) .
(1)计算: 2 - 1 + 12 - sin 30 ° ;
(2)化简并求值: 1 - a a + 1 ,其中 a = - 1 2 .
(1)计算: 12 + 3 tan 30 ° − | 2 − 3 | + ( π − 1 ) 0 + 8 2021 × ( − 0 . 125 ) 2021 ;
(2)化简求值: 2 n m + 2 n + m 2 n − m + 4 mn 4 n 2 − m 2 ,其中 m n = 1 5 .
(1)计算: 27 + ( 2 cos 60 ° ) 2020 - ( 1 2 ) - 2 - | 3 + 2 3 | ;
(2)先化简,再求值: ( x - 2 xy - y 2 x ) ÷ x 2 - y 2 x 2 + xy ,其中 x = 2 + 1 , y = 2 .
(1)计算: ( - 1 ) 2020 + ( π - 1 ) 0 × ( 2 3 ) - 2 ;
(2)先化简 ( x 2 x + 1 - x + 1 ) ÷ x 2 - 1 x 2 + 2 x + 1 ,再从 - 1 ,0,1中选择合适的 x 值代入求值.
计算: ( 1 2 ) - 1 + 2 cos 60 ° - ( 4 - π ) 0 + | - 3 | .
试题篮